The book is published, but the research goes on.
As I prepare to leave this sad but pleasant place behind me, I am working tirelessly to find someone to work tirelessly to get me speaking engagements. What is going to happen next is anyone's guess, but if I'm on my way that's a damn good start.
This is some old post stuff, but worth printing just to get it out of my waiting to post stack.
So we're going to go a little further into this capacitor theory of spiral intersection. What we're doing here is adding to the algorithm that defines the intersection to include what happens at the intersection in certain circumstances. We're also going to discuss why this happens the way it does to some extent and the models in three dimensional space that define 'inflection points' where the intersection yields to non-intersection which are not necessarily the equivalent of the very different places where the sin function changes the direction of the algorithm.
We have defined lengths of these overlaps and these defined lengths will give us a definition of "time" for the capacitor equations between t=0 and t=end of the overlap but we can solve for any quantum moment thereby allowing us to predict the future or the past at any point.
To understand this, we have the equivalent of time which is the length along the point of intersection. This generates a stacking of spirals which we're going to compare to current over a capacitor. Don't mistake this for actual current because we're not going to have the same effect. What differences?
Well for one thing, we're going to achieve stable higher states, not necessarily in every spiral intersection, but in the big bangs we're going to have the next higher time state as well as some significant discharge.
So let's take this analogy down the road a little ways and bear with me, because we're going to be do lots and lots of substitutions to get from the real world power source, to the algorithm power source of AuT.
Charging circuit-V/t is a time (here length) equation starts charging quickly that slows down gradually until it never quite reaches the charge of the power source. This type of equation is a good hint that it's driven by the quantum type features that otherwise define the universe.
V(t)=E(1-e^-t/RC) where E is the maximum voltage. This is how the intersection of two spirals look coming together.
When the intersection stops you get a discharge circuit which looks like:
I vs t; current starts out at the E/Re^-t/RC)
E is the power source. t is replaced with length and since we're solving for points we can pick one anywhere along this equation and solve it for a quantum moment.
RC is the time constant and is approximately .63 for the charging and .37 for the discharging circuit.
when t=rc then e^-1 is 1/e. e=(1+1/n)n as n approached infinity (in our case the maximum information in the universe.
Where R is the Resistence and C is the capacitance. We're not worried about actual electricity, we're only interested in the "building" of this type capacity so while we use Voltage, we're actually collecting spirals and they will, at some point in time (when you get to the non-overlap point [where overlap ends and which is an inflection point in the equation where charging of spirals leads to the dicharge of spirals EXCEPT where they have become stable due to the equation for stability which is essenitally F(n-2,n-1,n-adding those)^2^n for those accumulations of spirals where stability is attained.
So you derive the charging as V(t)=E(1-e^-t/RC) and I(0)=E/R(e^-t/RC) and discharging is
V(t)=QRCe^-t/RC and I(t)=Q/RCe^-t/RC but you don't fully discharge on one end and you discharge more than you would on the other end. At the ct3-4 interface, this 'discharge' to the extent there is a discharge, is our friend e=mc^2 but, of course, we have the other constant previously derived for ct4-5 where the factor (of course being F(n-2,n-1,n) is M(matter)=BH(blackhole stuff)x(times)q13^2^5 where q is a constant that makes up for the difference between the constant for the speed of light and this new constant
Q=EC(1-e^-t/RC)
The capacitor begins to push back against the power source when it begins to b
We're going to need some information for e so let's talk about why it is important to our spiral universe.
e=sum(from n=0 to n=infinity (or the total information in the universe)1/n(factorial) or sum1/n!=1+1/1+1/1*2+1/1*2*3
1,1,1/2,1/6,1/24.
The importance here has to do with probability theory which in a fixed environment becomes certainty theory. IF you have something happen 1 time out of n times then the probability of it happening is 1 time out of e (from 0 to n) or 1/e where e is summed calculated from 0 to n (and one can presume in AuT from 0 down to -n). n changes as universes build so that probability decreases steadily which allows for the combination of universes.
for the first universe 1 positive and 1 negative spiral the answer is 1, for the second univese it is 2, for the third it is 2.2 and so on. These changing probabilities, especially when n is the amount of bits of information in our universe (10^100 plus for any quantum) leads to a probability which is very close to the limits of e, but still not solved exactly allowing for minor variation.
Likewise it defines distribution (d(x)=1/sqr(2pi)*e^-1/2x^2) which again is solved for each universe starting with x=1 (technically the pre-universe has the solution 1/sqr(2pi)). Why important to consider? Because the solution for the distribution equation has inflection points (1, 2, 3, -1,-2,-3) where the direction changes (the undulating of a sin wave) which is the analogy of intersecting spirals (see the prior definition of the spiral using sin which can be replaced with a similar function to this one for distribution or, potentially, points of charge and discharge of our capacitors.
There are many ways to derive this. One is the first derivative shows a sin wave (y=f(x)), the first derivative y=f'(x) yielding a u-shaped curve, the second derivative shows the inflection point where this solution goes from positive to negative (y=f"(x)). These many ways to skin the cat don't change the outcome we are looking for which is a change in direction at a quantum point only solvable by having a finite amount of information (a finite e, a finite x)
Likewise we can solve for i (i^2=-1) in an information universe because you can have positive or negative information for the opposite spiral. For positive information 1*1=1, for negative information 1*1=-1. It doesn't work in our non-quantum view of the universe but might work perfectly well along the opposite spiral.
We're not using capacitors, of course, but the equations are derived below and the derivation is the same but not the results because of stable compression
https://www.youtube.com/watch?v=cVBNzJ-jRWw
https://www.khanacademy.org/math/differential-calculus/derivative-applications/concavity-inflection-points/v/calculus-graphing-using-derivatives
https://www.youtube.com/watch?v=cVBNzJ-jRWw
As I prepare to leave this sad but pleasant place behind me, I am working tirelessly to find someone to work tirelessly to get me speaking engagements. What is going to happen next is anyone's guess, but if I'm on my way that's a damn good start.
This is some old post stuff, but worth printing just to get it out of my waiting to post stack.
So we're going to go a little further into this capacitor theory of spiral intersection. What we're doing here is adding to the algorithm that defines the intersection to include what happens at the intersection in certain circumstances. We're also going to discuss why this happens the way it does to some extent and the models in three dimensional space that define 'inflection points' where the intersection yields to non-intersection which are not necessarily the equivalent of the very different places where the sin function changes the direction of the algorithm.
We have defined lengths of these overlaps and these defined lengths will give us a definition of "time" for the capacitor equations between t=0 and t=end of the overlap but we can solve for any quantum moment thereby allowing us to predict the future or the past at any point.
To understand this, we have the equivalent of time which is the length along the point of intersection. This generates a stacking of spirals which we're going to compare to current over a capacitor. Don't mistake this for actual current because we're not going to have the same effect. What differences?
Well for one thing, we're going to achieve stable higher states, not necessarily in every spiral intersection, but in the big bangs we're going to have the next higher time state as well as some significant discharge.
So let's take this analogy down the road a little ways and bear with me, because we're going to be do lots and lots of substitutions to get from the real world power source, to the algorithm power source of AuT.
Charging circuit-V/t is a time (here length) equation starts charging quickly that slows down gradually until it never quite reaches the charge of the power source. This type of equation is a good hint that it's driven by the quantum type features that otherwise define the universe.
V(t)=E(1-e^-t/RC) where E is the maximum voltage. This is how the intersection of two spirals look coming together.
When the intersection stops you get a discharge circuit which looks like:
I vs t; current starts out at the E/Re^-t/RC)
E is the power source. t is replaced with length and since we're solving for points we can pick one anywhere along this equation and solve it for a quantum moment.
RC is the time constant and is approximately .63 for the charging and .37 for the discharging circuit.
when t=rc then e^-1 is 1/e. e=(1+1/n)n as n approached infinity (in our case the maximum information in the universe.
Where R is the Resistence and C is the capacitance. We're not worried about actual electricity, we're only interested in the "building" of this type capacity so while we use Voltage, we're actually collecting spirals and they will, at some point in time (when you get to the non-overlap point [where overlap ends and which is an inflection point in the equation where charging of spirals leads to the dicharge of spirals EXCEPT where they have become stable due to the equation for stability which is essenitally F(n-2,n-1,n-adding those)^2^n for those accumulations of spirals where stability is attained.
So you derive the charging as V(t)=E(1-e^-t/RC) and I(0)=E/R(e^-t/RC) and discharging is
V(t)=QRCe^-t/RC and I(t)=Q/RCe^-t/RC but you don't fully discharge on one end and you discharge more than you would on the other end. At the ct3-4 interface, this 'discharge' to the extent there is a discharge, is our friend e=mc^2 but, of course, we have the other constant previously derived for ct4-5 where the factor (of course being F(n-2,n-1,n) is M(matter)=BH(blackhole stuff)x(times)q13^2^5 where q is a constant that makes up for the difference between the constant for the speed of light and this new constant
Q=EC(1-e^-t/RC)
The capacitor begins to push back against the power source when it begins to b
We're going to need some information for e so let's talk about why it is important to our spiral universe.
e=sum(from n=0 to n=infinity (or the total information in the universe)1/n(factorial) or sum1/n!=1+1/1+1/1*2+1/1*2*3
1,1,1/2,1/6,1/24.
The importance here has to do with probability theory which in a fixed environment becomes certainty theory. IF you have something happen 1 time out of n times then the probability of it happening is 1 time out of e (from 0 to n) or 1/e where e is summed calculated from 0 to n (and one can presume in AuT from 0 down to -n). n changes as universes build so that probability decreases steadily which allows for the combination of universes.
for the first universe 1 positive and 1 negative spiral the answer is 1, for the second univese it is 2, for the third it is 2.2 and so on. These changing probabilities, especially when n is the amount of bits of information in our universe (10^100 plus for any quantum) leads to a probability which is very close to the limits of e, but still not solved exactly allowing for minor variation.
Likewise it defines distribution (d(x)=1/sqr(2pi)*e^-1/2x^2) which again is solved for each universe starting with x=1 (technically the pre-universe has the solution 1/sqr(2pi)). Why important to consider? Because the solution for the distribution equation has inflection points (1, 2, 3, -1,-2,-3) where the direction changes (the undulating of a sin wave) which is the analogy of intersecting spirals (see the prior definition of the spiral using sin which can be replaced with a similar function to this one for distribution or, potentially, points of charge and discharge of our capacitors.
There are many ways to derive this. One is the first derivative shows a sin wave (y=f(x)), the first derivative y=f'(x) yielding a u-shaped curve, the second derivative shows the inflection point where this solution goes from positive to negative (y=f"(x)). These many ways to skin the cat don't change the outcome we are looking for which is a change in direction at a quantum point only solvable by having a finite amount of information (a finite e, a finite x)
Likewise we can solve for i (i^2=-1) in an information universe because you can have positive or negative information for the opposite spiral. For positive information 1*1=1, for negative information 1*1=-1. It doesn't work in our non-quantum view of the universe but might work perfectly well along the opposite spiral.
We're not using capacitors, of course, but the equations are derived below and the derivation is the same but not the results because of stable compression
https://www.youtube.com/watch?v=cVBNzJ-jRWw
https://www.khanacademy.org/math/differential-calculus/derivative-applications/concavity-inflection-points/v/calculus-graphing-using-derivatives
https://www.youtube.com/watch?v=cVBNzJ-jRWw
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