Aut and The battle with the periodic table 2 of 2

So the biathalon worked, even felt a little capable despite the earlier run and the historical knee problem which chased me to a pool over and over again.
The gymcation continues.

But you do not care about that.  You want to see where this is going and its going somewhere.

First let us note that molecular orbits are nothing more than potential and therefore match information arms in concept tying atomic and molecular structure to the earlier building blocks.  That alone is worth the price of admission, but AuT always has more than one reason for everything, right?  Ahh so funny, but so unappreciated.

Anyway, if you understand this I hope it blows your mind, if you don't I hope it amuses you.  My christmas gift, the solution of the periodic table without electron orbits based on AuT.

Part II-Dual Fractal Math and the Periodic Table

AuT up to ct5 results in dual fractal math and has also shown a tendency to memorize and build on prior solutions.  These can be applied to the periodic table to give a result which is based on AuT and NOT on a complex orbital mode.

N=4 applies because the weak force is binding Electrons (T-12) to Protons (T-16) to form Neutrons (ct4 complete; 10^16).

N=5 applies because the strong force is binding Protons and Neutrons along ct5 information arms.  In this regard, it is important to note the follows: 

Arm 1=16 matches

Arm 2=16*16=256.  The periodic table only has 118 features, less than ½ of this 256.   There is a shift far before black holes are reached from straight compression to molecular compression where different stable states between an atomic mass of 1 and 118 are stacked together.  There is simply not enough stability in the matrix to squeeze out enough ct1,2,3 and 4 to get past 118 aligned ct4 states until black hole compression is almost reached.

It is worth noting that Arm 3=256*16=4096.  Because of the complexity at ct5 in alignment you end up with a fractal within the above referenced fractal for the first 2 information arms which reflect ct4 states interacting with ct5 states.

Applying Dual Fractal Math we get this view for n=4 and n=5:

(see the book for dual fractal math drawings)

This is an example showing ct3, you can draw out the one used here for ct4 and 5 or you can buy a book.

Simplified: This is where you need the n=4 drawing which essentially is a four sided box, an 8 sided cube, a 16 cube of 4 of the 4 sided box and then a cube made from this 16 cube.  Get out a piece of graph paper and you can draw this in 5 minutes.

Then you have a 4 sided 5 cube (20 total units); a 40 cube and an 80 box made of 4 20 boxes.

While technically you are changing dimensions here, it is done with fractal math.

This model shows the presence of the weak force (n=4) where the proton and electron are binding to a neutron;

And the strong force (n=5) where protons and neutrons are being aligned along ct5 information arms.

The weak plus strong force reflect compression giving rise to molecular action.

The result suggested by the model above is:

H is a single unit as ct4.

As a hangover of ct4 compression, He is the 4x4 box from alignment of H and this is the stable form of Helium, but the charge state is 2.  This is the first match along the first 16 place ct5 information arm.

Then the ct5 arm takes over half the equation while the ct4 equation remains in place.

(At this point in the program you need to open up a copy of the periodic table showing mass and atomic number)

The two critical parts of this are (1) stability and (2) dual fractals, one for the ct4 elements (protons) and another for the ct5 elements (total Atomic Mass=P+N).

A.    Atomic Number

Column 2 has 8 charge places; column 3 has 16, column 4 has 36. 

Looking at the drawing for ct4 states it is:

Row 1: 2 across; Hydrogen (ct4) and Helium (two aligned ct4 states plus 2 neutrons to balance the fractal square)

Row 2: 8 across-matches fractal square (8) or the cube form of Helium.  The proton stable state is this 8 plus the 2 of helium=10.

Row 3: 8 across-with the prior solution it matches the fractal cube (16).  P stable=10+8

Row 4 and 5: 18 across-with the first row it matches the fractal cube of Rows 3+2+1: (2+16).  This remains stable for 4 and 5 just as 8 pus 8 remained stable for rows 2 and 3.

Row 4:Kr=18+10+8 or (2(n-1+n-2)).

Row 5:Xe=18+36=n-1+n-2.

The model up to this point looks like this:

2:8:8:18:18 corresponding to stable orbits of 2;10;18;36 (He;Ne;Ar;Kr;Xe).

Xe has a stable orbit of 54.  This corresponds to 3*18 so while you have the second fractal cube defining the number of solutions across, you have stacked the first 5 solutions or 3 times the prior-prior solution to get the observed stability or just the prior two solutions added.

Row 6: 18+14=32 across.  This is the second predicted fractal cube from above (detail below). 

Rn has a stable orbit of 86 corresponding to the second F-cube plus the prior solution.

Row 7:18+14=32 across.  This time the stable orbits of Og are 118 protons or the predicted 32 from the prior fractal plus the 86 of Rn.

This is ½ of the periodic table, charge, based on ct3 fractals.

And now for something relly weird, ct5 kicks in:

B.    Atomic Mass

Functioning in parallel with the Atomic number stability is the mass.

This starts with Helium at 4.

Row 2: Then it shifts to the 5 square (5x4=20). Observed=20.18 for Neon

Row 3: The next is the 5 cube (40).  Observed 39.8 (Ar)

Row 4: Then the next square 80. Observed 83.8 (Kr).  The Fractal model shows weakness here.

Row 5: The next cube would be 160, Xe is observed only at 131.  While the Fractal has broken down, this approximates Row 3 plus row 4 (120) (also Row 3 plus 4 plus 5 (140)).  Looking at charge, it appears that the mass should be based on the geometry of the prior two states added together; but it is also attempting to maintain its own internal geometry at 160,but it is beginning to fail because it cannot squeeze out enough intervening solutions to get there. This is likely the reason for stacking the Atomic Number fractal instead of going to the next one.

Row 6: The next square 320; Radon only at 222.  This approximates Row 5 (theorized as 140) plus Row 4 (80)=220 predicted. Note in the charge, the next fractal state has materialized.

Row 7: Og 118/294:  This matches Row 6 (4+5=220) plus Row 4 again (80) =300; or even Row 6 plus 3 plus 2 (60)=260.  Compare atomic mass.

C.    Summary

The strong plus strong force yields fusion, squeezing out lower ct states or reflecting the elimination of those lower states.  While it is viewed as a counterweight to electromagnetic repulsion, it appears more likely that the EM repulsion is absent due to the alternating alignment of the information and is a reason while the so called weak force results from the inability to reduce certain protons to neutrons to properly fill information arms.

The resulting mess can be seen by comparing, for example, H20 to Neon.

H20 can be viewed as “low energy” n=10

Neon is “high energy” n=10 binding.

What happens with the Neon, is that the lower ct states are squeezed out of a matrix allowing for 20 neutron states.  Electrons are essentially not present, although there is sufficient instability for them to exist.

In Water, the electrons are mathematically present even though there are 8 Neutrons and 8 protons.  There are also 2 additional protons because of mathematical alignment.

For Neon you have the weak force converting 10 neutrons. 

For H20 you have 6 neutrons so there is 40% less ct4 weak force. 

For Ne you have 20 strong force (alignment of 20 ct1 on the base 5 fractals above) pulling together 10 stabilized Protons and 10 N. 

For H20 you have 10P and 8N.  The protons are not stabilized. Instead you have a strong force alignment of 16 protons and neutrons and a destabilized strong force alignment of 2 hydrogens along ct5 information arms.  There is not enough compression to get to the Neon result but the forces generated are comparable.

The weak force finishes ct4.  Earlier versions of ct4 compression are seen as wave energy.  The strong force finished ct5.  We see this as atomic nucleus and molecular alignment.

What are orbits but unfilled information arms?

The result is a mathematical, charge free derivation of the periodic table in concept.

Now here is the fun part for me.  The building blocks of life.

Sugars are carbon, hydrogen and oxygen; the building blocks of life.  Amino acids add Nitrogen.

If we ignore the hydrogen except for what it is, we see 1/1; 6/12; 7/14 and 8/16 building which is very much an AuT result.

          The instability of Li, B and Be are tied to their inability to form stable geometric forms, 1 to 3 sides of the four sided fractal box for charge, uneven sides of the 5 unit box for compression, total mass.

Li: ¾ (odd/even)

Be 4/9 (Odd/odd)

B 5/11 (odd/odd)

          Carbon is 6/12 (even/even) which is more stable even though it fails to match the charge box and does not match a compression box.  It does, however, match a 2+4 charge and more importantly it has a 1:2 charge to mass ratio allowing a greater alignment of the ct4 and ct5 compression states.

          Nitrogen 7/14 (odd/even)  This also has the 1:2 charge to mass which continues in the periodic table with increasing instability (intervening lower states) once you get past the 3^rd row and introduce the next fractal state.

          However, before you get to the instability you have Oxygen at 8/16.

          Hydrogen supplies additional stability to mimic the next higher stable fractal state.

Lightning crackles in the background a mad laugh explodes from my throat as my wild white hair stands up to welcome the electricity, I look up at the roiled sky, raising my hands and shout in a maniacle scream, its alive!