A closer look at the hydrogen atom

I have not slept in over a week
except one night
when I did not sleep
but was a little better
I swam 3000 yrds,
then 2700 yards
the cold water wakes me
 i am healthy enough
nervous all the time
i am tired
i won't sleep tonight
i suppose
i am losing touch with things
people love the wretched
i am half an idiot savant
But the course, that is where I'm at.  I hoped this would shed some light on portions of the physics that were hidden and I am not disappointed.
I'm continuing to fall behind, but there are some very interesting features
and answers are coming.
This is an example.
I have destroyed the magic of time
Now to take a closer look at the hydrogen atom, 
a more complicated result without more complicated mathematics.

1.      A closer look at the hydrogen atom

The key point we are going towards is that the stable orbits for electrons reflect the places where the exchange rate between the nucleus and the first shell of electrons becomes stable for different ambient energy configurations.
Outer shells of electrons in more complicated orbits will reflect the same features.
While those calculations have not been done even for the Hydrogen atom, we can see they come from the standard orbital model.
For hydrogen we are looking at a “stable” electron proton pair.  This is a transitional state with a stable ct1 substitution rate.  However, the substitution rate can be increased with excited orbits which are transitional quantum changes: n=1,2,3, etc based on this formula: L=nh/2pi.

Likewise “a photon” is given off with a “frequency (wave length)” as you drop from one value of n to a lesser value indicating (by virtue of the wave) that it is more than one photon.  The energy given off is a function of the nh/2pi equation which translates easily into packets of ct1 exchange although pi has to have a universally applicable value (at least observable) and Planck’s constant has to be looked at in terms of ct1 exchange rate.  This is important because we need to know how much information is used in the calculation of pi, how many places are applicable.

The level of compression then varies within a range that does not completely destabilize as ct1 exchange rates increase.  The exchange of ct3 states as opposed to their replacement by ct1 exchange varies within this range without one totally substituting for the other.  It is a vibrational ct1 exchange as opposed to one which is destructive.

To the extent that waves are what are being viewed, it seems likely that these are an intermediary state between one dimensional photons and three dimensional neutrons with electrons and to a lesser extent protons being states that are transitions between two dimensional waves fixed 3 dimensional features of neutrons.  This raises the question of what are the transitional states, if they are neither waves nor 3 dimensional solids. 

The suggested result is that these electrons transition or "bounce" between the number of dimensions existing on either side of the inflection points depending on whether they are in the process of (compressing) building up or (decompressing) breaking down and the net averages that are represented.  What other choices would there be?

This suggests the uncomfortable (unstable) result that electrons would be transitioning between compressing towards a neutron state and breaking down to a wave state as it slowly transitions towards one state or the other. Frequency reflects the number of photons with the wave which are incremental because of the 2^n pairing possibly.  An examination of this transition vs the L=nh/2pi is worth considering.

The faster movement of electrons within the system is because the number of ct1 and ct2 substitutions vs bundled ct3 substitutions is greater than with a proton where the number of ct3 substitutions is greater, effectively bundled electrons or nearly that result.  

The alternative is to say that electrons are just probabilities which is not super-symmetric.  Instead the speed of ct1 substitutions is high because the transitions are unstable.