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Saturday, February 24, 2018

The slit test, and Ball of Fire

Gary Cooper said, in Ball of Fire, "The scientific conquest of an important subject is never dull."  While not as important as the delightful Barbara Stanwyck it is more applicable to what is happening here. 

Before I get too deeply into the slit test,let me say that the variations suggested in the article below have not be performed to see what information might be forthcoming.  Were I to have a candle and a match, I would certainly not have a slit or the time to make one.
AuT is necessarily a logic based system which is internally mathematically consistent. Any problems which might arise from a different test result would merely suggest the way the equations were examined needed to be tweaked, the underlying definitions of time,dimension and compression state remain inviolate.



1.      The slit test


We start at the end, the Heisenberg uncertain principle, you cannot measure the light passing through without changing the result.  This merely means that the math of the prior art is inadequate.
What we’re going to do is discuss what appears to be the reason for the slit test results and how to deal with them
First what happens when light passes through a slit?  We can assume that AuT is accurate and light moves between photonic states and wave states in a time free environment.  The reason is because time will not exist until you get to the ct3-ct4 transition at the earliest. (see the prior post on light).  While I have called this movement between states averaging, it is not an average over time since it is a pre-time change and this is part of the reason the test fails, for the same reason the Morley and Michelson experiment fails.  It is an exchange in pre-time and therefore so fast that we do not observe it.
So what happens when this transition occurs.  We can assume due to the two dimensions of waves and the one of photons, more photons pass through the slit than waves.  Once other the other side they reassemble based on the type of waves that arrived at the slit.
This happens in a pre-time environment which is important. This is the reason that we see the two separate states as a duality.  The "time" for recombination (compression and decompression followed by compression again and so on) is zero.  In the environment of super-symmetry there are discrete points for photons and waves.
This brings us to an issue that requires more consideration.  Why one wavelength and not another.  Why does light return to the original state after it passes through.  The reason has to do with substitution rates and different transitions and the transitions of the waves that result, but a more detailed discussion must wait.  The point is that the energy of a beam of light as a part of wavelength can change but how that occurs is a question for a later post. For now we’ll ignore what state the light returns to.
How can we prove this theory?  The answer is that there are several ways, none of which are satisfying because I cannot perform them.
Varying the length at which either light exits whichever slit is one way to observe this issue, but the speed with which they reassemble and the distance both suffer from the same problem, they have to approach a quantum length in order to see the result.
A similar way to accomplish this is to extend the length of the walls of the slit, although you  would have to deal with dissipation along the length.
The idea is the length is long enough or the slot hole small enough the wave length going in approaches photonic size and varies the type of wave moving through.

But otherwise, at any length which is measurable the transitional nature of the light is reestablished.

Let us take one look at the conversion that occurs in the photon to wave alteration.  This is rough and only an initial look, but all these observations must follow the basic rules or substitution rates and compression.
The wave spectrum is made up of waves of different wavelengths. The energy of the photon is inversely related to the wavelength of the wave: 
The energy of the photon is presumably a density issue since there is a constant rate change in terms of speed.
lambda = h*c/E where lambda is the wavelength, h is Plancks constant, c is the speed of light and E is the energy of the photon.   
The photons can be thought of as the particles in the light wave and as they are concentrated relative to the space,the wave length has to expand to accommodate them by allowing more ct1 around each one.





https://tsw.createspace.com/title/8176429

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