Building an algorithm-building a matrix 1

P=Sum(solns)F(series)=S(slnspos)F(s)(pi')+s(slnsneg)F(s)(pi')dx
F(s)=f(s)^2^n for compressed states
Somewhere in this equation "regional" geography is present.
One possibility for this comes from matrix solutions although pi' being an evolving value of pi provides for a limited amount of dimension.  Another element suggested is that for any value of x, each separate universe is altered for that value of x.  By "stacking" the universes you have the following:
1) A changing alignment
2) A changing value for each spiral for a given point
3) A matrix formed by one universe stacked on the prior universe.
Because the algorithm defining the universe is consistent, defining these matrix type solutions can be relatively simple for the initial universe, but change dramatically after even a few increases in x.
Compression occurs where solutions for a given group of numbers in the Matrix have common Positive and Negative Spiral Solutions at a sufficient concentration of the next lower compression state to form those compressed states.
When a group of people (government, institution) create a temporary compression state that is equivalent to a black hole (which is not stable unless it is exponential in size which is why we don't have tiny black holes swallowing planets as taught in K-physics) they are creating something they are compelled to create (including the billions of years of evolution to create the individuals involved) by this stacked spiral model.  This is why self determination is so seductive, we are working with such high values of x and in such concentrations, that the underlying features are completely hidden from our view.
So, using a simple example:
0,1,1,0 is one cycle plus 1 for space.   For this post (and probably any subsequent post unless I really work hard) we can never get to a matrix which is large enough to have even a single state of compression at the ct2 (photon) level.
For purposes of this example we are going to use "words" instead of drawing.
The first 0,1 transition uses a pi factor of 1.  It is worth nothing that the correct pi factor might be 4, but 1 appears to work better due to the evolving geometry of space, but for the K-physicist reading this we don't want to confuse them too much.
The second transition is also positive for pi although it is suggested it is negative.  So it's either 0,1 with a pi factor of 1+1/3 or 1-1/3 or 0,-1 with the same pi factor.
The third transition is also 0,1 if the second transition is negative or 0,-1. with the next pi factor, however by this time, the first transition of 0,1, the second is either 1,1 or -1,-1 .
Anyway we are only at 3 transitions.
There, however, another algorithm operating in the background.
This is the F-series which is not cycling and for the first transition is 1,1,2 at the point where the third transition has occurred.
There is one more element which is a little "too" k-physics for me, but it would have a more balanced universe where the first spiral also had a negative element.
In this case the first spiral would be "both" 01 and 0-1 then 11,-1-1; then 11,-1-1, the 00.  You would have this "space" "ride on" another underlying spiral going 1,1,2 or -1,-1,-2 which overlap to provide the features of compression or decompression whether the positive and negative features are approaching or moving away from each other for a given solution.
The enormous numbers explain stability since the solutions for these "carrying spirals" for these initial spirals have essentially infinite (from our perspective) stable lines before transitions seeing each right hand turn in the example below as a transition and growing according to the f-series equation.