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Saturday, April 12, 2014

NLT 23-the simple equation for compression as a function of force creation

We are all hung up on traditional physics which is only our perspective.
NLT suggests that the things that we see as "outward" forces, might actually be the anti-forces to compression. That is when you force something one way the corresponding force in the other way (reflected in newton's laws of all things) we perceive as forces.
Time ravels one way or the other and forces are created or combine in a way that we would otherwise envision in traditional physics as matter/anti matter reactions.
So lets solve this for what we know:
Integration P(d1-f1, d2-f2,d3-f3,d4-f4 etc)dt.  In this equation each d represents a stage of matter.  For this case, we'll jump around a little bit and we'll look at d4+f4 being that form of time capable of spin, what we call matter.  F is the corresponding force (gravity, electromagnetic forces, clock time).
All of these start at zero, d1=f1, d2=f2, etc. and all are conserved as far as we can tell.
There are permutations that will complicate this, but for purposes of this solution we are going to ignore these (for example N(neutron)=P(proton+electron).
So let's take one of these equations that we understand, the rotational to non=rotational.  I.E. E=mc^2 where c=m/t and energy accelleration is m/t^2 which explains why e=mc^2 instead of mc if you think about it.  If you can't think about it, the wait long enough and maybe I'll get around to explaining it.
Now, knowing the transition from energy to the rotational dimension (in this case d3-f3 to d4-f4)
Several things are apparent from this solution.  First we know that clock time has a value =mc^2 since clock time is the aspect of time, the force of time in this case, that comes into existence with this transition, rotation allows for clock time as it were.  It's a little more complicated because the forces are interchangeable, but we'll have to come to that later.
One possible theorem is that the compression is "consistent" which would provide that (in this case) the transition from d2-f2 to d3-f3 is along the same power of compression.  Now in the past, what we've looked at is this transition being from non-electronmagnetic to electromagnetic energy.  Like the movement from energy to matter, this may also be staged, but need not be staged.  Just for fun, we'll stage it and assume that we're looking at the transition to create the weak and strong forces which is why we have an extra transition.  So we have rotational potential which comes to exist either before (what I'd suggest) or after the creation of clock time.  Alternatively, time is a result of the the weak and strong forces.  This discussion, unfortunately, must also wait till later; but rotational time changes seem more "timely" as it were.
So getting back to the transitions, we're looking at d2-f2 to d4-f4 being either on the scale of m2c^4 or m4c^6 but mass doesn't exist and neither does clock time.
The better view, as nearly as I can tell would be to use (for simplification purposes) the point charge along a single vector (vectors being dimension, the creation of space/time can be viewed from one of these at a time).
F(e)=(q/4pier^2)r' where q=electric charge, r is the position (in terms of x, y and z if you go that way), r' is the unit vector of r (for the one set of positions)
Going back one step (the creation of space and gravity from time going non-linear d1+f1 to d2+f2)
F(g)=m(-GMr'/r^2).
The obvious suggestion is that the scales of transition remain the same where r corresponds to c.
Now some of you are thinking the obvious, that c is a much "larger" number than these vector numbers and, of course, you couldn't be more wrong, since these vector numbers change according to the distance between them which are, at best, a multiple of planck length perhaps, as is suggested before, on the scale of the square of plank lengths.  Hence, the reason these transitions are so hard to see (they are really small).
We need to go a little deeper to understand this, but it's pretty late, so we'll just have to wait.
The purpose was to understand you have this type of transition:
P(d1+f1, d2+f2,d3+f3,d4+f4)dt
Time is non linear dt=0.
Time goes non linear (step one in the big bang)
P(d1+f1)dt which is a function of m(-gmr'/r^2) for gravity and therefore for space; dt=zero for all the other d(s) and f(s); space transitions into energy and
p1(d1+f1)=p2(d1+f1,d2+f2)dt, f2 being electromagnetic forces that is energy is created from space; see the F(e) equation above.
Now we're going to just stick in something we already know which is the movement of energy into matter but we are going to hold out and not allow for rotational movement which allows for matter of various forms to exist so: P2(d1+f1,d2+f2)dt=P3(d1+f1,d2+f2,d3+f3)dt and finally clock time exists which is the whole e=mc^2 and the first point at which we, as three dimensional being, can really pick up directly on the transitions;
And finally we're going to add the creation of strong and weak forces (lumping them together for reasons which will have to wait till later) which allow for rotational movement which is F4 in this progression where matter in the form of energy transitions to hard matter down from electrons where p3=the whole shebang (to use technical language)dt.
Now we could have strong and weak forces first and energy to matter conversion (rotation) second.  After a nuclear explosion (or other radioactive decay) the question is do we lose spin or do we lose the strong and weak forces or do we lose both together?
And that's all for now.




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