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Sunday, December 17, 2017

AuT Derivation of creation

We discussed and pointed out the unusual pattern of gravitational development in the last post.
Sadly, as with all things in AuT the solutions are both deceptively simple and, as the complexity of the universe indicates, convoluted in application.
In this case we saw several things.
One was the suggested "double tap" in the pattern.  I'm not entirely comfortable with that one.
The other was the "return to two" which doesn't really do much for me either.
The initial (not final) pattern was 2, n+2, -n.
The problem with this solution, complex and discomforting as it is; because the other solutions are not forgotten.  when you have, for example -5, you still have the 2,-3 and 1 results in place.  And all of these co-existing solutions cycle together at different rates. 
In the prior post we only show the beginning of the first 10 cycles.  We have, just in this cycle of the big bang, 13.5billion x 1.07x10^39x356x12x60x60 quantum solution changes where this mixed up morass cycles. Since our big bang is one of billions of big bangs (albeit the first ones are very short, the very rough solution suggest from 1-10 there were 3 or 6 of them depending on how they are counted, a number that suggests over 100 billion big bangs, do the math) its not hard to imagine a universe as complicated as the one we observe.

The idea of what numbers from that list come into effect, do some drop out?  Not likely, so they continue in the background in some fashion. The exact methodology is not so much in doubt as very complicated. For example, you may have a simple cycling of results
0 -1
1 1
2 -3
3 -3 5
4 -3 5 -7
5 5 -7
6 5 -7
7 5 -7
8 -7
9 -7
10 -7
11

In the example above, -1,1,-1,1 would continue forever, as would -3, 5 and -7 always a part of whatever solution comes next.  This result is suggested, and it would significantly change the scale of the results, but would still allow for cycling of compressive vrs decompressive results. The very long periods between big bangs and big anti-bangs suggests something different,that the results drop out in some way, but this is not a required difference.

The subsequent changes derive from 32/27; 2^4/3^3 or 2^n/3^n-1 or f(1)^n/f(n+1)^n-1 where f is the Fibonacci number for n.

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