NLC-solving for pi in a non-linear space-part one from the third edition

When we look at NLC we come up with some unusual formula for the universe which are a function of information and not actual locations.  When we look at pi (and there are many different ways to look at pi) we find ourselves, for example, looking at a convergent infinite series of the type:

pi=4/1-4/3+4/5-4/7+4/9-4/11 etc

There are other ways of showing this through equations which converge quicker and integration of change e.g.

pi=2xint(from -1 to 1) or (1-x2)^1/2dx

This is not considered coincidentally similar to the equations of clock times going positive and negative and just as we have multiple orbit types and phase changes in NLT, so we find an equation for pi that reflects a phase change.

In this example, pi is represented by the same type of “informational” bit transformation: 4/2^n transitioning to 4/2*n from 0 to infinity.  There are several places for this phase changes, the most suggested by non-linearity is when you go from n=0 to n=1, although it could be at n=3.  Either way you would have 4/1-4/2+4/4-4/6,etc.  The transition, however, can be viewed differently if you want to accept orbits as pointed out below.

One question of linearity is why don't forces cancel out the corresponding dimensional aspects and take everything back to a non-linear state?  The best answer is that we exist in a non linear state, but we have linear states at quantum “points”, even if they are largely illusory.  This proposition assumes that at any point in time, we exist with a prepackaged past and future, and that all of these points in time (quantum points, of course) exist at once.

 A longer discussion will follow where we see this type of stepped transition in irrational (or non-linear) numbers such as pi which can only be calculated by way of example.  4/1-4/3+4/4/5-4/7.  Nothing this transition is also a function of 2, and if there are “orbits” associated with the calculation of pi, which would provide a vehicle for a fixed solution, that “orbital” change occurs at the point here 2^n transitions from n=0 to n=1, the 0 element being the first orbit, the n=1 being the second so that the solution in terms of orbits looks like this: 4/2^0-4/2^1*2+4/2^1*3-4/2^1*4, etc where the transition from 0 to 1 represents a phase transition.  Phase transitions are reflected in time dilation as will be discussed further. 

Using the idea of phase transitions, you can arrive at pi being the sum from n=zero to infinity of 4/(2^n’)*n noting that there may also be a summation of n’ associated with certain changes in n, in this case n=0 to n=1.  There is no reason why there cannot be other phase changes before or after the n’0 to n’1, the next one looking something like this: 4/2^2*x where x may start over as 1 or x may be some other function.  At what point in the solution this phase change would occur is important in solving pi and it represents the transition from an irrational number with no solution in ct4 to an irrational number with a solution, presumably in CT3 or lower, perhaps only present in ct1 where there is, after all, no true clock time because there is only one coordinate change at once and the most likely place, based on time dilation and gravity where you would expect to find these types of transitions.