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Saturday, August 12, 2017

AuT and the missing link 2 and frozen negativity

Let's talk curvature and lightspeed, and yes in aut you can have both in a non-dimensional framework before space time arises.
Aut suggests there are two states, not positive and negative but positive coming from a state capable of being positive or negative which we interpret as negative only because of how it appears in ct4 interactions.  Put another way, even what you think of positive and negative is wrong and only I see them correctly and for what they are.  There is no positive and negative, there is only negative and a frozen state of negativity.  Ha!
In fact, all the suggestions of the math, which continues in this post, suggest that the 0' state manifests itself primarily as a negative state in ct1 and ct2 interactions and only appears locked into the positive, inflexible state, as a result of the algorithm which manipulates the otherwise very flexible universe, thereby greatly reducing its flexibility.  In the process it provides for information arm exponential growth (64).
Now you don't know what you're doing so this is going to be a little hard to handle, but in the next set of posts we're going to show that math actually proves this to be the case and you already know this because you know that AuT is right and that everything else before it is...not so much wrong, as misinterpreted.
Momentarily, post wise, we're going to show how that factorial feature becomes important, but for the moment, just to prove AuT is right and everything else is wrong we're going to look at the very limited case where x is very small.
siny
siny
siny
siny
siny
2*y/(pi0^(2n+1)
2*y/(pi1^(2n+1)
2*y/(pi2^(2n+1)
2*y/(pi3^(2n+1)
2*y/(pi4^(2n+1)
y=1
note-starting at red should be summed top line n=0
-1.5
-6
3
1.2
0.75
-0.84375
-54
6.75
0.432
0.105469
6.103515625
90.36413399
0.294695081
0.021901692
0.003995

What this shows is the answer that you get when n=1 (that is the sum from 0 to infinitiy stops at 1) which allows us to drop the factorial in the pi vs sin equation and get the 2y/pi(x)^2n+1.
While the higher states are shown, only at ct0 and ct1 can you have n equal to 1 because it takes more information, quite a bit more, to get to the next higher states.  Indeed, the transition from space to ct2 is 1:256 and this is important and the derivation of dimension gives rise to this result as is indicated below.
You will get the math that gives rise to the answer above, but if readers from 10 different countries comment on this post, I'll put the spreadsheets up in tehir entirety, otherwise you can do your own darn spreadsheets.  Doesn't really matter, however, because whether the math is right or wrong is pretty irrelevant.  I've figured out the basis of space/time, unified field theory (to the extent you can call these things fields), and basically reduced every other physicists primary work up till now...well primary; but I've also proved it doesn't matter.

Now what's really critical in all of this is that as predicted by AuT (sort of had to be predicted, because the math said it worked this way) you have negative features where you have ct0 and ct1.  Starting at ct2 things change relatively dramatically because you have the whole "squared" result that yields a positive, but this shows the way that negative time states vary.  The red line at the bottom is important only because it shows the transition from negative states to positive states during the transitions for ct0 and ct1 but this is not mathematically accurate because it isn't a proper summation for ct0 or ct1 for a number of reasons that I will, given time, get in to.  Of course, I may well go blind or die of hunger before I get this finished and they will do documentaries  in the future where they will say, why didn't they buy this genius' books or give him a grant and elderly physicists will go on and say stupid stuff like, nobody believed him, no body told publishers to reach out to him (but its so obvious!); he was such a horses behind (well didn't he prove that whether you're a horses behind or not is irrelevant?); aha!  there you have it, doesn't matter whether we gave him grants or bought his books, his theory proves that (oh yeah).
But I digress.
The next post will take these numbers and show what they teach about compresssion.  Feel free to speculate about it in the interim, but the big lesson is in this post.
Note that this are for y=1degree (not 1 radian); but the ratios remain constant regardless of the angle in question for ct1 and ct0 because there are no distances involved in those and because they use pure, flexible negative states..
Now its not critical to worry about any particular result because this is the sin function for a closed system of one point, but ct0 and ct1 don't have dimension so while ct2,3,4 and 5 (pi2,pi3,pi4, pi5) require dimension to comprehend them acurately, that is not the case for the first two solutions.
siny siny siny siny siny
2*y/(pi0^(2n+1) 2*y/(pi1^(2n+1) 2*y/(pi2^(2n+1) 2*y/(pi3^(2n+1) 2*y/(pi4^(2n+1)
y=1 256 note-starting at red should be summed top line n=0
-384 -1536 768 307.2 192
-216 -13824 1728 110.592 27
1562.5 23133.2183 75.44194075 5.606833195 1.022609
-25735.71875 -3696972826 1110.964238 5.829395476 0.300248

While changes in y are signficant (as will be pointed out) the main significance lies in whole number mathematics because angles only arise in higher ct states just as distance does.  Hence, at the pi0/pi1 interface we can, theoretically ignore changes in n and y and, in fact, for n=1, changes in y don't affect ratios between ct states or ratios between ct states.

siny
siny
siny
siny
siny
2*y/(pi0^(2n+1)
2*y/(pi1^(2n+1)
2*y/(pi2^(2n+1)
2*y/(pi3^(2n+1)
2*y/(pi4^(2n+1)
y=1
2.56E+02
note-starting at red should be summed top line n=0
-384
-1536
768
307.2
192
-216
-13824
1728
110.592
27
1562.5
23133.2183
75.44194075
5.606833195
1.022609
-25735.71875
-3696972826
1110.964238
5.829395476
0.300248

The ratios of change don't vary with y.
The only ratio that is unadultrated is the ratio (64) of pi0 (for n=1) to pi1.
This is the coversion rate of ct1 space information arms, that is you get 2^n for ct1 space=4 and n=2 (ct2) in the drawing (Figure 1) above at this transition point allowing space to transition acording to a geo function related directly to the evolving value of pi predicted by AuT.
To get to this exact number you get 1.185185185 degrees (185 repeating), -1 to -64 and 64 is 256 divided by 4 and a true relationship must, in some way, be where light speed is derived, suggesting light is...what 1:64 instead of 1:256, the ratio of substitution rate for space to ct2?
So we are looking for curvature, a place where you go from a non-dimensional state to a stacked state and we get to within a factor of 2^2 to the stacking equation itself and the lightspeed substitution rate.  You can actually see this relationship in the prior posts showing the growth of information in information arms in figure 1.
Does this represent the origin of transition states?  A coincidence?  Something more or less important?
And .185 repeating is...what? other than the division problem of any two numbers resulting from the pi0, pi1 ratio for n=1?
We'll come back to this, but if you want to see the math...

siny siny siny siny siny
2*y/(pi0^(2n+1) 2*y/(pi1^(2n+1) 2*y/(pi2^(2n+1) 2*y/(pi3^(2n+1) 2*y/(pi4^(2n+1)
y=1 1.185185185185 note-starting at red should be summed top line n=0
-1.777777778 -7.111111111 3.555555556 1.422222222 0.888889
-1 -64 8 0.512 0.125
7.233796296 107.0982329 0.349268244 0.025957561 0.004734
Anyway you cut it, you can begin to see that curvature can be derived from a relationship that is independent of dimension allowing for ct1 to move to ct2 through some mathematical relationship tying the states together, here connecting the two initial states and the first state from non-linearity to linearity at the same rate as reflected by the more or less constant compression formulat, 2f(n)^(2^n) which goes along with the F-series creation of linearity and the information arm 2^n creation of compressed states.


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